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    • 1. 发明专利
    • Transmission function estimation device, transmission function estimation method, and transmission function estimation program
    • 传输函数估计设备,传输函数估计方法和传输函数估计程序
    • JP2014021603A
    • 2014-02-03
    • JP2012157692
    • 2012-07-13
    • Denso Corp株式会社デンソーNagoya Institute Of Technology国立大学法人 名古屋工業大学
    • MUKAI YASUHIKOMORITA YOSHIFUMIUKAI HIROYUKIIWASAKI MAKOTOOTAKE HIROYASUKANO RYO
    • G06F17/17
    • G06F17/10G01H1/00
    • PROBLEM TO BE SOLVED: To provide a transmission function estimation device, a transmission function estimation method and a transmission function estimation program capable of reducing an arithmetic operation load, and accurately calculating the transmission functions of an entire system.SOLUTION: An estimation formula for estimating a transmission function of an object to be measured is acquired (S101), and frequency response characteristics as data of a frequency area are acquired (S102). Whether the arithmetic operation of the estimation formula is addition/subtraction or multiplication/division is determined for each arithmetic operation (S103), and if the arithmetic operation is determined to be addition/subtraction (S103: YES), time response characteristics g, gare calculated by converting frequency response characteristics G, Gto be added/subtracted from a frequency region into a time region (S104), and the addition/subtraction of the time response characteristics g, gis operated in the time region (S105). Then, the calculated addition/subtraction result g+gis reconverted into the frequency region to obtain G+G(S106). Thus, it is possible to perform the arithmetic operation of the estimation formula for estimating the transmission functions of an entire system without calculating the transmission function of a partial system.
    • 要解决的问题:提供一种能够减少算术运算负荷并且精确地计算整个系统的发送功能的发送功能估计装置,发送功能估计方法和发送功能估计程序。解决方案:估计公式 获取被测量物体的发送功能(S101),获取作为频率区域的数据的频率响应特性(S102)。 对于每个算术运算,确定估计公式的算术运算是否加减运算(S103),如果运算运算被确定为加法运算(S103:是),则时间响应特性g,加雷 通过将频率响应特性G,Gto从频率区域变换为时间区域(S104)以及在时间区域中操作的时间响应特性g,gis的相加/减去而计算的(S105)。 然后,将计算的加法/减法结果g + gis转换到频率区域以获得G + G(S106)。 因此,可以在不计算部分系统的发送功能的情况下,进行用于估计整个系统的发送功能的估计公式的算术运算。
    • 2. 发明专利
    • Control system and vehicle steering control system
    • 控制系统和车辆转向控制系统
    • JP2014035569A
    • 2014-02-24
    • JP2012174856
    • 2012-08-07
    • Denso Corp株式会社デンソーNagoya Institute Of Technology国立大学法人 名古屋工業大学
    • MUKAI YASUHIKOMORITA YOSHIFUMIUKAI HIROYUKIIWASAKI MAKOTOWADA TAKESHI
    • G05B11/32
    • B62D6/003B62D5/008B62D5/0463B62D6/00B62D6/08B62D7/159G05B11/32G05B11/58G05B15/02
    • PROBLEM TO BE SOLVED: To easily obtain a non-interference control that reduces an influence by mutual interference between outputs in a control system controlling a control target outputting a plurality of control amounts.SOLUTION: A control system 10 calculating an input to a control target 20 of m inputs and n outputs (m=n where m and n are a positive integer of 2 or more) is configured to set a combination of an input and an output. A feedback controller 13 calculates control inputs ν1, ν2...νn to a non-interference controller 14 for each set combination so as to track a current value to a target value on the basis of a deviation between the target values r1, r2...rm of control amounts y1, y2...yn and the current value. The non-interference controller 14 implements non-interference control for each set combination so as to reduce an influence by mutual interference between n pieces of control amounts y1, y2...yn. Accordingly, since the number of combinations of the input/output, which should consider interference, can be largely reduced, the non-interference control can be easily obtained.
    • 要解决的问题:为了容易地获得减少控制输出多个控制量的控制目标的控制系统中的输出之间的相互干扰的影响的无干扰控制。解决方案:控制系统10计算到控制目标的输入 m个输入和n个输出中的20个(m = n,其中m和n是2或更大的正整数)被配置为设置输入和输出的组合。 反馈控制器13针对每个组合组合向非干扰控制器14计算控制输入&ngr; 1,&ngr; 2 ...&ngr; n,以便根据目标值之间的偏差来跟踪目标值 控制量y1,y2 ... yn的目标值r1,r2 ... rm和当前值。 非干扰控制器14对每个组合进行不干扰控制,以便减少n个控制量y1,y2 ... yn之间的相互干扰的影响。 因此,由于可以大大减少应该考虑干扰的输入/输出的组合的数量,因此可以容易地获得非干扰控制。
    • 3. 发明专利
    • Electric power steering device
    • 电动转向装置
    • JP2010064663A
    • 2010-03-25
    • JP2008234215
    • 2008-09-12
    • Denso CorpNagoya Institute Of Technology国立大学法人 名古屋工業大学株式会社デンソー
    • OGASAWARA TERUKIMUKAI YASUHIKOTSUCHIDA NORIOUKAI HIROYUKIMORITA YOSHIFUMIYOKOI AKITOSHIIWASAKI MAKOTOMATSUI NOBUYUKI
    • B62D6/00B62D5/04B62D101/00B62D113/00B62D119/00
    • PROBLEM TO BE SOLVED: To improve the feeling of operation without the need of final tuning work in the case where a mechanism giving a strong inertia torque exists near a steering wheel in a steering system of EPS1. SOLUTION: According to the EPS1, an assist motor 2 forms the working point of the inertia torque in the steering system on the side of steered-wheels relative to the side of a torque sensor 5, and a microcomputer 23 includes a correction means 30 for correcting the sum of a basic assist current-carrying amount and an inertia compensation current-carrying amount. In addition, the correction means 30 calculates a correction amount according to the steering wheel-side inertia torque and add the correction amount to the calculated value of an adding means 29. By this way, mutual interference between the basic assist current-carrying amount and the inertia compensation current-carrying amount, which results from the structural characteristics of the torque sensor 5, can be alleviated so that the feeling of the operation can be improved without the need of the final tuning work even in the case where the mechanism or the like giving the strong inertia torque exists near the steering wheel in the steering system. COPYRIGHT: (C)2010,JPO&INPIT
    • 要解决的问题:在EPS1的转向系统中的方向盘附近存在强惯性转矩的机构的情况下,为了提高操作感而不需要最终的调谐作业。 解决方案:根据EPS1,辅助电动机2形成转向系统中相对于转矩传感器5侧的转向系统侧的惯性转矩的工作点,微计算机23包括校正 用于校正基本辅助载流量和惯性补偿载流量之和的装置30。 另外,校正单元30根据方向盘侧惯性转矩来计算校正量,并将校正量与加法单元29的计算值相加。由此,基本辅助载流量与 可以减轻由扭矩传感器5的结构特性引起的惯性补偿载流量,从而即使在机构或机构的情况下也可以改善操作感,而不需要最终的调谐功能 就像在转向系统的方向盘附近存在强惯性力矩一样。 版权所有(C)2010,JPO&INPIT
    • 4. 发明专利
    • Motor drive device
    • 电机驱动装置
    • JP2013215040A
    • 2013-10-17
    • JP2012083876
    • 2012-04-02
    • Denso Corp株式会社デンソー
    • ARAI KANTAKABUNE HIDEKIMUKAI YASUHIKO
    • H02P27/06B62D5/04B62D6/00B62D119/00H02P6/12
    • H02P29/022H02P25/22H02P29/0241H02P29/028H02P29/032
    • PROBLEM TO BE SOLVED: To provide a motor drive device that comprises a plurality of systems of inverter sections and when any inverter section fails, cuts a power supply relay connected to the fault system of inverter section to stop power supply, which prevents a circuit element on the fault system from being broken by an inductive voltage generated by a motor due to rotation by external force.SOLUTION: In a motor drive device, when failure detection means 71 detects a failure of an inverter section 50 at a first system, drive control means 41 stops driving of the inverter section 50, and opening/closing control means 31 turns off a first power relay 21 and turns on a second power relay 22, of the power supply opening/closing section 20. While driving of the inverter section 50 is being stopped, an inductive voltage generated in a first winding group 80 of a motor 800 due to rotation by external force passes from the inverter section 50 through the second power relay 22 and further passes through a parasitic diode of the first power relay 21 to return to a battery 15. This prevents breakage of a circuit element on the broken system.
    • 要解决的问题:提供一种包括多个逆变器部分的电动机驱动装置,并且当任何逆变器部分失效时,切断连接到逆变器部分的故障系统的电源继电器以停止供电,从而防止电路元件 在电机驱动装置中,当故障检测装置71在第一系统检测到逆变器部分50的故障时,驱动控制 装置41停止驱动逆变器部分50,并且打开/关闭控制装置31关闭第一电力继电器21并打开电源开/关部分20的第二电力继电器22.在驱动逆变器部分50时 由于外力的转动,电动机800的第一绕组组80产生的感应电压从逆变器部50通过第二电力继电器22而进一步产生 通过第一功率继电器21的寄生二极管来返回到电池15.这防止了断开的系统上的电路元件的损坏。
    • 5. 发明专利
    • Steering control system
    • 转向控制系统
    • JP2013001369A
    • 2013-01-07
    • JP2011138165
    • 2011-06-22
    • Nippon Soken Inc株式会社日本自動車部品総合研究所Denso Corp株式会社デンソー
    • KAWASE YUHORI MASAFUMIMUKAI YASUHIKO
    • B62D6/00B62D5/04B62D101/00B62D113/00B62D119/00
    • B62D5/008B62D5/0466B62D6/002
    • PROBLEM TO BE SOLVED: To provide a compact and lightweight steering control system for preventing breakage of a component.SOLUTION: An ECU 40 calculates a basic transfer ratio on the basis of a steering angle detected by a steering angle sensor 31. The ECU 40 calculates a corrected transfer ratio by correcting the calculated basic transfer ratio on the basis of a position of a rack 6. Specifically, the ECU 40 calculates the corrected transfer ratio by correcting the basic transfer ratio so that a value of the basic transfer ratio is reduced as the rack 6 moves from a predetermined first position near one end of a moving range to the side of the one end or as the rack 6 moves from a predetermined second position near the other end of the moving range to the side of the other end. The ECU 40 determines either the basic transfer ratio or the corrected transfer ratio as the transfer ratio on the basis of the position of the rack 6. The ECU 40 controls drive of a first actuator 22 on the basis of the determined transfer ratio.
    • 要解决的问题:提供一种紧凑且轻便的转向控制系统,用于防止部件断裂。 解决方案:ECU40基于由转向角传感器31检测到的转向角来计算基本传送比.ECU40通过基于位置的位置校正计算出的基本传送比来计算校正传送比率 具体地,ECU 40通过校正基本传送比来计算校正的传送比,使得当机架6从移动范围的一端附近的预定的第一位置移动到基本传送比的值时,基本传送比的值减小 一侧或者当机架6从移动范围的另一端附近的预定的第二位置移动到另一端的侧面时。 ECU40基于机架6的位置来确定基本传送比或校正传送比作为传送比。ECU 40基于所确定的传送比来控制第一致动器22的驱动。 版权所有(C)2013,JPO&INPIT
    • 7. 发明专利
    • Motor drive apparatus, electric power steering apparatus using the same, and program
    • 电机驱动装置,使用其的电力转向装置和程序
    • JP2011142744A
    • 2011-07-21
    • JP2010002062
    • 2010-01-07
    • Denso Corp株式会社デンソー
    • MUKAI YASUHIKOURYU NOBUHIKO
    • H02P27/06B62D5/04B62D6/00B62D113/00B62D119/00
    • B62D5/0487B62D5/0403B62D5/046H02P29/032
    • PROBLEM TO BE SOLVED: To provide a motor drive apparatus capable of appropriately controlling a motor, even immediately after the start of driving of the motor.
      SOLUTION: The motor drive apparatus 1 drives a motor 10 by a first motor drive part 11 and a second motor drive part 12. The first motor drive part 11 includes a first inverter 20 for supplying current to a first winding set 87 for driving the motor 10. Likewise, the second motor drive part 12 includes a second inverter 30 for supplying current to a second winding set 88 for driving the motor 10. A determination control unit 50, that controls the motor drive apparatus 1, waits for all the failure detection processing to terminate in the first motor drive part 11 and the second motor drive part 12, and then it starts supplying current to the first winding set 87 in the first motor drive part 11 and current supply to the second winding set 88 in the second motor drive part 12, at substantially the same time.
      COPYRIGHT: (C)2011,JPO&INPIT
    • 要解决的问题:提供即使在电动机开始驱动之后也能够适当地控制电动机的电动机驱动装置。 电动机驱动装置1通过第一电动机驱动部11和第二电动机驱动部12驱动电动机10.第一电动机驱动部11包括:第一逆变器20,用于向第一绕组组87供给电流, 类似地,第二电动机驱动部分12包括用于向用于驱动电动机10的第二绕组组88提供电流的第二逆变器30.控制电动机驱动装置1的判定控制单元50等待所有电动机 故障检测处理终止于第一电动机驱动部11和第二电动机驱动部12,然后开始向第一电动机驱动部11中的第一绕组87提供电流,并向第二绕组组88供电 第二电动机驱动部12,基本上同时。 版权所有(C)2011,JPO&INPIT
    • 8. 发明专利
    • Steering control device
    • 转向控制装置
    • JP2011051412A
    • 2011-03-17
    • JP2009200385
    • 2009-08-31
    • Denso Corp株式会社デンソー
    • MUKAI YASUHIKO
    • B62D6/00B62D5/04B62D101/00B62D119/00
    • PROBLEM TO BE SOLVED: To provide a steering control device capable of securing responsiveness of steering, regardless of the size of assist gain.
      SOLUTION: A torque sensor 30 detects steering torque based on a difference between a rotation angle of a steering shaft 10 input with the steering torque therein and a rotation angle of a steering shaft 20 connected to a tire 5 of a vehicle. A control part 50 has an input part 51 input with the steering torque detected by the torque sensor 30, calculates turning assist torque based on the steering torque and operates an electric motor 40 to impart the turning assist torque to the tire 5. The control part 50 secures gain margin and phase margin of an open loop frequency response characteristic from the input part 51 to the torque sensor 30 by prescribed values or more, and makes gain of a closed loop frequency response characteristic from the steering torque to an angle of the tire 5 higher than steady gain in a prescribed frequency band.
      COPYRIGHT: (C)2011,JPO&INPIT
    • 要解决的问题:提供一种能够确保转向的响应性的转向控制装置,而与辅助增益的大小无关。 解决方案:扭矩传感器30基于与其中的转向扭矩输入的转向轴10的旋转角度和连接到车辆的轮胎5的转向轴20的旋转角度之间的差异来检测转向转矩。 控制部件50具有输入部件51,输入部件51具有由转矩传感器30检测出的转向转矩,根据转向转矩来计算转弯辅助转矩,并对电动机40进行动作,将转弯辅助转矩赋予轮胎5.控制部 50将开环频率响应特性的增益裕度和相位裕度保证从输入部51到转矩传感器30的规定值以上,并且使得从转向转矩到轮胎角度的闭环频率响应特性的增益 5高于规定频带的稳定增益。 版权所有(C)2011,JPO&INPIT
    • 9. 发明专利
    • Vehicular power supply system
    • 车用电源系统
    • JP2013144499A
    • 2013-07-25
    • JP2012005524
    • 2012-01-13
    • Denso Corp株式会社デンソー
    • MUKAI YASUHIKOKABUNE HIDEKIYAMAMOTO TOSHIHISA
    • B60R16/02B60L1/00B60L3/04B60T13/74B62D5/04
    • B62D6/00B60L1/003B60L3/00B60L3/0092
    • PROBLEM TO BE SOLVED: To provide a vehicular power supply system that prevents shutting off the electric power supply to a steering assist drive part by shutting off a power feeding path caused by a fault of a main machine, in the vehicular power supply system in which the steering assist drive part of the electric power steering device is supplied the electric power from the main battery.SOLUTION: In a vehicular power supply system 10, a main battery 20 supplies electric power to both a main machine drive part 32 which drives a main motor 33 for driving a vehicle, and a steering assist drive part 42 which drives a steering assist motor 43 of a power steering apparatus. A main machine shutting part 30 which can shut off power supply to the main machine drive part 32, and an auxiliary machine shutting part 40 which can shut off power supply to the steering assist drive part 42 are provided in parallel to the main battery 20. As long as the auxiliary machine shutting part 40 is connected, power supply to the steering assist drive part 42 is continued even when the main machine shutting part 30 shuts off the power supply.
    • 要解决的问题:提供一种车辆供电系统,其在车辆供电系统中,通过在主机的故障中切断由于主机故障引起的供电路径来防止切断向转向辅助驱动部的电力供给,其中, 电动助力驱动部的转向辅助驱动部从主电池供给电力。解决方案:在车辆电源系统10中,主电池20向驱动主电池的主机驱动部32提供电力 用于驱动车辆的马达33以及驱动动力转向装置的转向辅助马达43的转向辅助驱动部42。 与主电池20并联设置有可以切断向主机驱动部32供电的主机停止部30和切断向转向辅助驱动部42供电的辅机停止部40。 只要连接辅机停止部40,即使主机关闭部30关闭电源,也能够继续向转向辅助驱动部42供电。
    • 10. 发明专利
    • Motor drive unit and electric power steering device using the same
    • 电机驱动单元和使用该电动机的电动转向装置
    • JP2012111474A
    • 2012-06-14
    • JP2010277966
    • 2010-12-14
    • Denso Corp株式会社デンソー
    • URYU NOBUHIKOMUKAI YASUHIKONAKAMURA KOICHI
    • B62D6/00B62D5/04
    • B62D5/0403B62D5/0484B62D5/0487H02P29/032
    • PROBLEM TO BE SOLVED: To provide a compact and low-cost multi-system motor drive unit capable of suppressing operational fluctuation when any one of systems therein fails.SOLUTION: When a first system fails at a time t0 in a dual system motor drive unit, a power supply relay is interrupted, and output current of an inverter becomes 0 (a). A power control means doubles a current supplied to an inverter of a normal second system, as compared with during normal operation, so as to compensate for the electric power supplied by an inverter of the first system (b), and keeps the total inverter output constant before and after the failure (g). Thereby, operational fluctuation can be suppressed. Furthermore, after an elapse of a predetermined period (at a time tX), the electric power supplied by the second system is gradually reduced. Thereby, a time period while the inverter of the normal system is under excessive load is shortened. Thus, a large inverter does not need to be used, and the electric motor drive unit can be compact and low in cost.
    • 要解决的问题:提供一种紧凑型和低成本的多系统电机驱动单元,其能够在其中任何一种系统失效时抑制操作波动。

      解决方案:当双系统电机驱动单元中第一个系统在时间t0故障时,电源继电器中断,变频器的输出电流变为0(a)。 功率控制装置与正常操作相比,将提供给正常第二系统的逆变器的电流加倍,以补偿由第​​一系统(b)的逆变器提供的电力,并保持总逆变器输出 故障前后不变(g)。 由此,能够抑制运转波动。 此外,经过预定时间段(在时间tX),由第二系统提供的电力逐渐减小。 因此,正常系统的逆变器处于过载状态的时间段缩短。 因此,不需要使用大型逆变器,电动机驱动单元的结构紧凑,成本低。 版权所有(C)2012,JPO&INPIT