会员体验
专利管家(专利管理)
工作空间(专利管理)
风险监控(情报监控)
数据分析(专利分析)
侵权分析(诉讼无效)
联系我们
交流群
官方交流:
QQ群: 891211   
微信请扫码    >>>
现在联系顾问~
热词
    • 7. 发明公开
    • 단일 명령어를 이용한 다수 모드에서의 AES 암호화 또는암호 해독 수행
    • 在单一指令下执行多种模式的AES加密或解码
    • KR1020080084752A
    • 2008-09-19
    • KR1020080024067
    • 2008-03-14
    • 인텔 코포레이션
    • 딕슨,마틴체누패티,스리니바스구에론,샤이
    • G06F21/00G06F9/06
    • H04L9/0631G06F9/30007H04L9/0637H04L9/28H04L2209/12
    • A system and a method for performing AES(Advanced Encryption Standard) encryption/decryption in a plurality of modes by a single instruction are provided to enable processors to perform the AES encryption/decryption in a plurality of modes by the single instruction. An AES encryption instruction(310) couples a plaintext value and a second value logically to generate a coupled result, and encrypts the coupled result to generate an encrypted result by using an AES algorithm and a key. The AES encryption instruction performs XOR between the plaintext value and a second value to generate the coupled result. A first register stores the second value and a second register stores the key. The AES encryption instruction stores the encrypted result to the first register. The second value is the previous encrypted result or zero. The length of the plaintext value and the encrypted value is 128 bits.
    • 提供通过单个指令执行多种模式的AES(高级加密标准)加密/解密的系统和方法,以使得处理器能够通过单个指令以多种模式执行AES加密/解密。 AES加密指令(310)逻辑地耦合明文值和第二值以产生耦合结果,并且通过使用AES算法和密钥加密耦合结果以生成加密结果。 AES加密指令在明文值和第二值之间执行XOR以生成耦合结果。 第一寄存器存储第二值,第二寄存器存储该键。 AES加密指令将加密结果存储到第一个寄存器。 第二个值是先前加密的结果或零。 明文值和加密值的长度为128位。