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    • 1. 发明授权
    • High strength, high ductility titanium-alloy and process for producing
the same
    • 高强度,高延展性钛合金及其制造方法
    • US6063211A
    • 2000-05-16
    • US750627
    • 1997-02-07
    • Seiichi SoedaHideki FujiiHiroyuki OkanoMichio Hanaki
    • Seiichi SoedaHideki FujiiHiroyuki OkanoMichio Hanaki
    • C22C14/00
    • C22C14/00
    • A high strength, high ductility titanium alloy comprising O, N and Fe as strengthening elements and the balance substantially Ti, the contents of the strengthening elements satisfying the following relationships (1) to (3):(1) from 0.9 to 2.3% by weight of Fe,(2) up to 0.05% by weight of N, and(3) an oxygen equivalent value Q, which is defined by the formula mentioned below, of 0.34 to 1.00Q=[O]+2.77[N]+0.1[Fe]wherein [O] is an oxygen content (% by weight), [N] is a nitrogen content (% by weight) and [Fe] is an iron content (% by weight), the titanium alloy having a tensile strength of at least 700 MPa and an elongation of at least 15%. Part of Fe may be replaced with Cr and/or Ni. Fe, Cr and Ni may be introduced from a carbon steel or stainless steel, or they may be introduced from sponge titanium containing these elements.
    • PCT No.PCT / JP96 / 01078 Sec。 371日期1997年2月7日 102(e)1997年2月7日PCT PCT 1996年4月19日PCT公布。 出版物WO96 / 33292 日期:1996年10月24日高强度高延展性钛合金,其中O,N和Fe为强化元素,余量基本为Ti,强化元素的含量满足下列关系式(1)〜(3):(1) 0.9〜2.3重量%的Fe,(2)至多0.05重量%的N,和(3)由下式所定义的氧当量值Q为0.34〜1.00 Q = [O] + 2.77 [N] +0.1 [Fe]其中[O]为氧含量(重量%),[N]为氮含量(重量%),[Fe]为铁含量(重量%), 钛合金的拉伸强度为700MPa以上,伸长率为15%以上。 部分Fe可以用Cr和/或Ni代替。 Fe,Cr和Ni可以从碳钢或不锈钢引入,也可以从含有这些元素的海绵钛引入。