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    • 42. 发明授权
    • Plasma display panel driver circuit having two-direction energy recovery through one switch
    • 等离子显示面板驱动电路,通过一个开关进行双向能量回收
    • US07327334B2
    • 2008-02-05
    • US10908706
    • 2005-05-24
    • Bi-Hsien ChenYi-Min HuangYi-I LuYung-Chan Chou
    • Bi-Hsien ChenYi-Min HuangYi-I LuYung-Chan Chou
    • G09G3/28
    • G09G3/2965G09G2330/023
    • A charging/discharging circuit of a plasma display panel (PDP) driver has a first inductance having a first end connected to the first side of the panel capacitor, a first diode having an anode coupled to a second end of the first inductance, a second diode having a cathode coupled to a cathode of the first diode, a second inductance having a first end coupled to an anode of the second diode and a second end connected to the second side of the panel capacitor, a third diode having a cathode coupled to the second end of the first inductance, a fourth diode having an anode coupled to an anode of the third diode and a cathode coupled to the first end of the second inductance, and a switch coupled between the cathode of the first diode and the anode of the third diode.
    • 等离子体显示面板(PDP)驱动器的充电/放电电路具有第一电感,第一电感具有连接到面板电容器的第一侧的第一端,具有耦合到第一电感的第二端的阳极的第一二极管, 二极管,具有耦合到所述第一二极管的阴极的阴极,第二电感,其具有耦合到所述第二二极管的阳极的第一端和连接到所述面板电容器的第二侧的第二端;第三二极管,具有阴极, 所述第一电感的第二端,具有耦合到所述第三二极管的阳极的阳极和耦合到所述第二电感的所述第一端的阴极的第四二极管,以及耦合在所述第一二极管的阴极和所述第一二极管的所述阳极之间的开关 第三个二极管。
    • 44. 发明申请
    • Driver Circuit for Plasma Display Panels
    • 等离子显示屏驱动电路
    • US20060238448A1
    • 2006-10-26
    • US10908610
    • 2005-05-19
    • Bi-Hsien ChenYi-Min HuangShin-Chang LinLiang-Che Cho
    • Bi-Hsien ChenYi-Min HuangShin-Chang LinLiang-Che Cho
    • G09G3/28
    • G09G3/2965
    • A driver circuit for plasma display panels is provided. The claimed driver circuit includes four switches and an energy recovery circuit coupled to an equivalent capacitor of a plasma display panel. The present energy recovery circuit includes a first unit, coupled to ground and the X side of the equivalent capacitor, for passing current of charging/discharging the equivalent capacitor from the X side and/or Y side; and a second unit, coupled to the first unit and the Y side of the equivalent capacitor, for passing current of charging/discharging the equivalent capacitor from the Y side. With the aid of four voltage sources, it is not necessary for the present energy recovery circuit of the driver circuit to adopt capacitors for charging/discharging the equivalent capacitor of the plasma display panel.
    • 提供了一种用于等离子体显示面板的驱动电路。 所要求的驱动器电路包括四个开关和耦合到等离子体显示面板的等效电容器的能量恢复电路。 本能量恢复电路包括耦合到地的第一单元和等效电容器的X侧,用于从X侧和/或Y侧通过对等效电容器进行充电/放电的电流; 以及耦合到等效电容器的第一单元和Y侧的第二单元,用于从Y侧传递对等效电容器进行充电/放电的电流。 借助于四个电压源,驱动电路的本能量恢复电路不需要采用用于对等离子体显示面板的等效电容器进行充电/放电的电容器。
    • 45. 发明授权
    • Method for driving a plasma display panel
    • 驱动等离子体显示面板的方法
    • US06943757B2
    • 2005-09-13
    • US10064674
    • 2002-08-06
    • Jih-Fon HuangYi-Min HuangShin-Tai Lo
    • Jih-Fon HuangYi-Min HuangShin-Tai Lo
    • G09G3/294G09G3/296G09G3/10G09G3/28G09G3/30G09G5/00
    • G09G3/2965G09G3/294G09G2310/06
    • A method for driving a plasma display panel (PDP). The PDP includes a first electrode and a second electrode. Initially provide the first electrode with a first voltage V1. Next, provide the second electrode with a second voltage V2 that is higher than the first voltage V1 during a first time interval. Then, provide the second electrode a third voltage V3 that is lower than the first voltage V1 during a second time interval. In the first time interval, a first voltage difference D1 between the first electrode and the second electrode equals the second voltage V2 minus the first voltage V1. During the second time interval, a second voltage difference D2 between the first electrode and the second electrode equals the third voltage V3 minus the first voltage V1.
    • 一种用于驱动等离子体显示面板(PDP)的方法。 PDP包括第一电极和第二电极。 首先为第一电极提供第一电压V 1。 接下来,在第一时间间隔期间向第二电极提供高于第一电压V 1的第二电压V 2。 然后,在第二时间间隔内向第二电极提供低于第一电压V 1的第三电压V 3。 在第一时间间隔中,第一电极和第二电极之间的第一电压差D 1等于第二电压V 2减去第一电压V 1。 在第二时间间隔期间,第一电极和第二电极之间的第二电压差D 2等于第三电压V 3减去第一电压V 1。