会员体验
专利管家(专利管理)
工作空间(专利管理)
风险监控(情报监控)
数据分析(专利分析)
侵权分析(诉讼无效)
联系我们
交流群
官方交流:
QQ群: 891211   
微信请扫码    >>>
现在联系顾问~
热词
    • 1. 发明授权
    • Duplex stainless steel, and its manufacturing method
    • 双相不锈钢及其制造方法
    • US5733387A
    • 1998-03-31
    • US776806
    • 1997-02-04
    • Yong Deuk LeeKwang Tae KimBong Un KimYong Heon Lee
    • Yong Deuk LeeKwang Tae KimBong Un KimYong Heon Lee
    • C21D8/00C21D8/02C22C38/00C22C38/44C22C38/58
    • C21D8/0226C21D8/005C22C38/001C22C38/44C21D2211/001C21D2211/005C21D8/021C21D8/0263
    • A duplex stainless steel consisting of a ferrite phase and an austenite phase is disclosed which is superior in the hot ductility, the high temperature oxidation resistance, the corrosion resistance and the impact toughness. The duplex stainless steel is applied to marine facility and the like. The duplex stainless steel which consists of a ferrite phase and an austenite phase is composed of in weight %: less than 0.03% of C, less than 1.0% of Si, less than 2.0% of Mn, less than 0.04% of P, less than 0.004% of S, less than 2.0% of Cu, 5.0-8.0% of Ni, 22-27% of Cr, 1.0-2.0% of Mo, 2.0-5.0% of W, and 0.13-0.30% of N. Or there are further added one or two elements selected from a group consisting of: less than 0.03% of Ca, less than 0.1% of Ce, less than 0.005% of B and 0.5% of Ti. Further, the ratio (Cr.sub.eq /Ni.sub.eq) of the Cr equivalent (Cr.sub.eq) to the Ni equivalent (Ni.sub.eq) is 2.2-3.0. Further, the weight ratio (W/Mo) of the W to Mo is 2.6-3.4. That is, the duplex stainless steel of the present invention satisfies the above condition, and the Ni.sub.eq and Cr.sub.eq are defined as follows: Ni.sub.eq =%Ni+30.times.%C+0.5.times.%Mn+0.33.times.%Cu+30.times.(%N-0.045), Cr.sub.eq =%Cr+Mo+1.5.times.%Si+0.73.times.%W.
    • PCT No.PCT / KR96 / 00084 Sec。 371日期1997年2月4日 102(e)1997年2月4日PCT PCT 1996年6月5日PCT公布。 第WO96 / 39543号公报 日期:1996年12月12日公开了一种由铁素体相和奥氏体相组成的双相不锈钢,其在热延展性,耐高温氧化性,耐腐蚀性和冲击韧性方面优异。 双相不锈钢应用于海洋设施等。 由铁素体相和奥氏体相组成的双相不锈钢由重量%组成:小于0.03的C,小于1.0的Si,小于2.0的Mn,小于0.04的P,少 超过0.004%的S,小于2.0%的Cu,5.0-8.0%的Ni,22-27%的Cr,1.0-2.0%的Mo,2.0-5.0%的W和0.13-0.30%的N.或者 进一步添加一种或两种选自以下的元素:小于0.03%的Ca,小于0.1%的Ce,小于0.005%的B和0.5%的Ti。 此外,Cr当量(Creq)与Ni当量(Nieq)的比(Creq / Nieq)为2.2-3.0。 此外,W与Mo的重量比(W / Mo)为2.6〜3.4。 也就是说,本发明的双相不锈钢满足上述条件,Nieq和Creq定义如下:Nieq =%Ni + 30x%C + 0.5x%Mn + 0.33x%Cu + 30x(% 0.045),Creq =%Cr + Mo + 1.5×Si + 0.73×W。