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1. 发明专利

JPH1151692A VARIABLE RELUCTANCE RESOLVER TO DIGITAL CONVERTER 失效
公开(公告)号：JPH1151692A
公开(公告)日：1999-02-26
申请号：JP12701798
申请日：1998-05-11
申请人： KOLLMORGEN CORP
发明人： VLAHU SASO P
IPC分类号： G01B7/30 , G01B7/00 , G01D5/20 , G01D5/245 , G01P3/488 , H02K24/00
摘要： PROBLEM TO BE SOLVED: To determine a speed digitally as the difference between two consecutive angular position samples by providing a look up table and correcting the sinθ and cosinθ values. SOLUTION: A stator is a tubular laminated iron shell S having teeth S1-S4 and C1-C4 projecting inward. A reference winding 16 is wound round respective teeth and energized from a reference modulation source. A secondary sine winding 14 is wound round respective teeth S1-S4 and a secondary cosine winding 15 is wound round C1-C4. A rotor R has salient poles P1, P2 and the position of the rotor R determines reluctance coupling between the reference winding and the secondary windings 14, 15. A signal to be generated in sine winding 14 has an amplitude which is a low accuracy approximation of sinθθis the angular position of shaft) and the cosine winding 15 generates a signal having an amplitude which is a low accuracy approximation of cosinθ.

2. 发明专利

JPH1137794A DIRECT RESOLVER FOR DIGITAL CONVERTER 失效
公开(公告)号：JPH1137794A
公开(公告)日：1999-02-12
申请号：JP12761498
申请日：1998-05-11
申请人： KOLLMORGEN CORP
发明人： VLAHU SASO P
IPC分类号： G01D5/245 , H03M1/64
摘要： PROBLEM TO BE SOLVED: To provide a direct resolver with higher resolution by deciding an octant value based on sine value and cosine value of a resolver, obtaining tangent value for linearization of the octant value, inverting a linearized value of even numbered octant, and adding the octant value to the linearized value. SOLUTION: A sine signal and a cosine wave signal are generated respectively at stationary secondary coils 14 and 15 of a resolver 10, then, through buffers 20 and 30, differential amplifiers 21 and 31, phase decoders 22 and 32, and filters 23 and 33, converted with A/D converter 24 and 24. A microcomputer 12 compares the sine value and cosine value, then compares polarity and relative magnitude for deciding an octant value. Between the sine value and the cosine value, one with smaller absolute value is divided by one with larger absolute value to obtain a tangent value, and corrected to the close to a linear value against an angle θ with an index table, and an eventual value against the angle θis decided using the octant value. The linear value of even number octant value is inverted, while 3 bit code value of octant taken as highest-order 3 bit, which is added to a linear value as lowest-order bit.

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