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    • 62. 发明专利
    • Power display device
    • 电源显示设备
    • JP2012225776A
    • 2012-11-15
    • JP2011093794
    • 2011-04-20
    • Panasonic Corpパナソニック株式会社
    • MUROI YOSHINORI
    • G01R22/00G01R11/00G01R21/00
    • PROBLEM TO BE SOLVED: To provide a power display device allowing display of measured power consumption while suppressing consumption of unnecessary power.SOLUTION: A power display device 10 comprises: a display 1 to display measured electric energy measured by an electric energy measurement device 20 to measure electric energy supplied from a commercial power supply to a dwelling unit; a clock part 3 for timing; and a human detection sensor 7 to detect presence of a person. If the time given by the clock part 3 is in a prescribed time zone and the human detection sensor 7 detects a person, the measured electric energy is displayed on the display 1.
    • 要解决的问题:提供一种能够显示测量的功率消耗同时抑制不需要的电力的消耗的电力显示装置。 电力显示装置10包括:显示器1,用于显示由电能测量装置20测量的测量电能,以测量从商用电源向住宅单元供应的电能; 时钟部分3用于定时; 以及检测人的存在的人体检测传感器7。 如果由时钟部分3给出的时间在规定的时间段内并且人体检测传感器7检测到人,则测量的电能被显示在显示器1上。(C)2013,JPO和INPIT
    • 63. 发明专利
    • Distributed power generating system
    • 分布式发电系统
    • JP2012220330A
    • 2012-11-12
    • JP2011086026
    • 2011-04-08
    • Panasonic Corpパナソニック株式会社
    • OTANI AKIHITOKAKE SHINOBUKAKO HIROAKINAGASATO HIROSHIKATO GENDO
    • G01R22/00G01R35/00H01M8/04H02J3/38H02M7/48
    • Y02E60/50
    • PROBLEM TO BE SOLVED: To provide a distributed power generating system capable of correcting deviation of zero point (offset value) in measured power by providing a signal inverting means that inverts the positive and negative of a current signal from a current sensor to thereby reset the sum of calculated power value to zero.SOLUTION: A signal integration means 110 integrates a normal current signal and a current signal inverted by signal reverting means 109 for the same period of time. When the integrated value is substantially zero, a control means 112 calculates a first power based on the normal current signal and a voltage signal and a second power based on the inverted current signal and the voltage signal for the same period of time, and sets the sum of the first power and the second power to zero to thereby correct the zero point of the power value in an arithmetic circuit 111.
    • 要解决的问题:提供一种能够通过提供将来自电流传感器的电流信号的正和负反相的信号反相装置来提供能够校正测量功率中的零点(偏移值)的偏差的分布式发电系统, 从而将计算的功率值的和重置为零。 解决方案:信号积分装置110将正常电流信号和由信号恢复装置109反相的电流信号整合在相同的时间段内。 当积分值基本上为零时,控制装置112基于反相电流信号和相同时间段的电压信号,计算基于正常电流信号和电压信号和第二功率的第一功率,并将 第一功率和第二功率之和为零,从而校正运算电路111中功率值的零点。版权所有:(C)2013,JPO&INPIT
    • 64. 发明专利
    • Information processor, information processing method, program, and information processing system
    • 信息处理器,信息处理方法,程序和信息处理系统
    • JP2012212344A
    • 2012-11-01
    • JP2011078074
    • 2011-03-31
    • Sony Corpソニー株式会社
    • KAMATA YASUNORIKAWASHIMA HIROSHINOMA HIDEKI
    • G06Q10/00G01R21/00G01R22/00
    • G06Q10/06
    • PROBLEM TO BE SOLVED: To grasp an environmental load amount for each individual.SOLUTION: An information processor comprises: an acquisition unit for acquiring personal identification information for identifying an individual; a control unit for generating association information by associating the personal identification information acquired by the acquisition unit with an environmental load amount which is a load amount imposed on the environment by the individual; and a storage unit for storing the association information generated by the control unit. The control unit may associate the personal identification information with a power consumption amount which is an amount of electric power consumed by using the information processor, as the environmental load amount. Also, the acquisition unit may acquire history information about actions of the individual, and the control unit may associate the personal identification information with an environmental load amount acquired by analyzing the history information.
    • 要解决的问题:掌握每个人的环境负荷量。 解决方案:信息处理器包括:获取单元,用于获取用于识别个人的个人识别信息; 控制单元,用于通过将由获取单元获取的个人识别信息与作为由个体对环境施加的负载量的环境负荷量相关联来产生关联信息; 以及存储单元,用于存储由控制单元生成的关联信息。 控制单元可以将个人识别信息与通过使用信息处理器消耗的电力量的功率消耗量相关联作为环境负载量。 此外,获取单元可以获取关于个人的动作的历史信息,并且控制单元可以通过分析历史信息将个人识别信息与获取的环境负荷量相关联。 版权所有(C)2013,JPO&INPIT
    • 65. 发明专利
    • Load estimation method and load estimation system for transformer
    • 变压器的负荷估计方法和负荷估计系统
    • JP2012205432A
    • 2012-10-22
    • JP2011068922
    • 2011-03-25
    • Tokyo Electric Power Co Inc:The東京電力株式会社
    • HIROSE KENTAROMABUCHI HIROYUKIOGIWARA YOSHINORI
    • H02J3/00G01R22/00
    • PROBLEM TO BE SOLVED: To provide a load estimation method and a load estimation system for transformer that estimate the load on a transformer from an unspread bank of a high-function type power meter by utilizing a user having a high function type power meter.SOLUTION: The load estimation method includes: acquiring load curves, monthly power consumptions, contract capacities, and categories of industry of new type users (300); calculating average curves by industry by totaling the load curves (302); calculating estimated error rates from the average curve by industry and the load curves (304); calculating monthly power consumption rates by the users (306); calculating error functions by industry from monthly power consumption rates and the estimated error rates (308); acquiring monthly power consumptions, contract capacities, and categories of industry from all users of transformers (310); calculating monthly power consumption rates by the users (312); calculating individual error rates from the error functions by industry and monthly power consumption rates (314); calculating estimated loads by multiplying the average curves by industry by the contract capacities and making corrections with the individual error rates (316); and calculating a maximum load on the transformer by totalizing estimated loads (318).
    • 要解决的问题:提供一种用于通过利用具有高功能型功率的用户从高功能型功率计的未扩展组估计变压器上的负载的变压器的负载估计方法和负载估计系统 仪表。

      解决方案:负载估计方法包括:获取负载曲线,月耗电量,合同能力和新型用户行业类别(300); 通过总计负载曲线计算工业平均曲线(302); 根据行业平均曲线和负荷曲线计算估计误差率(304); 用户计算每月电力消耗率(306); 按月消耗率计算误差函数和估计误差率(308); 从变压器的所有用户(310)获取每月电力消耗,合同能力和行业类别; 用户计算每月功耗率(312); 根据行业和月耗电率计算误差函数的个体差错率(314); 通过将工业平均曲线乘以合同能力并对单个错误率进行修正来计算估计负荷(316); 以及通过累加估计的负载来计算变压器上的最大负载(318)。 版权所有(C)2013,JPO&INPIT

    • 66. 发明专利
    • Network system and control method of power sensor
    • 电力传感器网络系统与控制方法
    • JP2012194752A
    • 2012-10-11
    • JP2011057921
    • 2011-03-16
    • Sharp Corpシャープ株式会社
    • URATA SHIGERU
    • G06Q10/00G01R11/00G01R22/00
    • PROBLEM TO BE SOLVED: To provide a network system and a control method of a power sensor which enable the power sensor to turn on the light more efficiently.SOLUTION: A controller 100 includes a communication interface 105 for communication with at least one power sensor and at least one human sensor, and a processor 110 which, when receiving information on the existence of a person from at least one human sensor through the communication interface, makes at least one power sensor turn on the light, and when receiving information on the nonexistence of a person from at least one human sensor, makes at least one power sensor turn off the light.
    • 要解决的问题:提供能够使功率传感器更有效地接通光的功率传感器的网络系统和控制方法。 解决方案:控制器100包括用于与至少一个功率传感器和至少一个人体传感器通信的通信接口105,以及处理器110,当从至少一个人体传感器接收到有人存在的信息时 所述通信接口使至少一个功率传感器接通所述光,并且当接收到来自至少一个人体传感器的人的不存在的信息时,使至少一个功率传感器关闭所述光。 版权所有(C)2013,JPO&INPIT